SAT Preparation Tools

1. This problem can be solved using a proportion. If there are 2 rest areas every 12 miles, there will be x number of rest areas on 4356/2, or 2178 miles of highway? 2/12 = x/2178, solving for x = 363. Choice C is correct.

2. Group 1 + Group 2 + Neither - Both = 75. In this case, 50 + 30 + Neither - 11 = 75. Neither = 6. Choice B is correct.

3. The cost of repairs = Total cost of parts + Total cost of labor. The total for the parts is $350 + $150 + $25 = $525. The total cost for labor = ($45) (3.5) = $157.50. The total cost to fix the car is $525 + $157.50 = $682.50, or Choice C.

4. 27 / 550 = 1 / 20. Choice D is correct.

5. Triangles with equal sides and equal angles are congruent. Choice B is correct.

6. We can solve this by plugging in numbers. Let's assume the original square was 10 inches x 10 inches; it's area was therefore 100 square inches. If we add 3 inches to its length and subtract 3 inches from its width, its new area is (10 + 3)(10 - 3) = (13)(7)= 91. This is 9% less, which is answer choice A.

7. A circle that is centered at the origin and passes through point (-7, 0) has a radius of 7. Therefore, its area is 49 , which is answer Choice D.

8. f(-1) = (-1)(-1) -4(-1) + 3 = 1 + 4 + 3 = 8. Choice D is correct.

9. The mean is 39.8, or Choice D.

10. We can solve by using a proportion. 12/500 = x / 14,280. x= 342.7 = 343. Choice C is correct.

11. Choice B is correct, -11/84.

12. The repeating pattern is 04321, which includes 5 digits. The 49th digit is 2, or Choice C.

13. Use the factorial formula to solve: 7! / 3! = (7 x 6 x 5 x 4 x 3 x 2 x 1) / (3 x 2 x 1) = 840. Choice C is correct.

14. (9)(9)(9) (27)(27) = 531,441, which is (729)2. Choice C is correct.

15. m =1/16. Choice A is correct.

16. If x2 + 3x - 18= 0, then (x + 6)(x - 3) = 0. So, x = 3, -6. Choice D is correct.

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